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5x^2-15x-2x-6=0
We add all the numbers together, and all the variables
5x^2-17x-6=0
a = 5; b = -17; c = -6;
Δ = b2-4ac
Δ = -172-4·5·(-6)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{409}}{2*5}=\frac{17-\sqrt{409}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{409}}{2*5}=\frac{17+\sqrt{409}}{10} $
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